4z+5=7z-39

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Solution for 4z+5=7z-39 equation: 



4z+5=7z-39

We move all terms to the left:

4z+5-(7z-39)=0

We get rid of parentheses

4z-7z+39+5=0

We add all the numbers together, and all the variables

-3z+44=0

We move all terms containing z to the left, all other terms to the right

-3z=-44

z=-44/-3

z=14+2/3

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