2,6-5y=8(3/2y-0,1)

Solution for 2,6-5y=8(3/2y-0,1) equation:

2.6-5y=8(3/2y-0.1)

We move all terms to the left:

2.6-5y-(8(3/2y-0.1))=0


Domain of the equation: 2y-0.1))!=0

y∈R


We multiply all the terms by the denominator


-5y*2y+(2.6)*2y-0.1))-(8(3-0.1))=0

We add all the numbers together, and all the variables

-5y*2y+(2.6)*2y-0.1))-(8(2.9))=0

We add all the numbers together, and all the variables

-5y*2y+(2.6)*2y=0

We multiply parentheses

-5y*2y+5.2y=0

Wy multiply elements

-10y^2+5.2y=0

a = -10; b = 5.2; c = 0;
Δ = b2-4ac
Δ = 5.22-4·(-10)·0
Δ = 27.04
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5.2)-\sqrt{27.04}}{2*-10}=\frac{-5.2-\sqrt{27.04}}{-20}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5.2)+\sqrt{27.04}}{2*-10}=\frac{-5.2+\sqrt{27.04}}{-20}
$