4z+12+z+3=4

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Solution for 4z+12+z+3=4 equation: 



4z+12+z+3=4

We move all terms to the left:

4z+12+z+3-(4)=0

We add all the numbers together, and all the variables

5z+11=0

We move all terms containing z to the left, all other terms to the right

5z=-11

z=-11/5

z=-2+1/5

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