4(2n+1)=6(4n+2)+4

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Solution for 4(2n+1)=6(4n+2)+4 equation: 



4(2n+1)=6(4n+2)+4

We move all terms to the left:

4(2n+1)-(6(4n+2)+4)=0

We multiply parentheses

8n-(6(4n+2)+4)+4=0



We calculate terms in parentheses: -(6(4n+2)+4), so:

6(4n+2)+4

We multiply parentheses

24n+12+4

We add all the numbers together, and all the variables

24n+16

Back to the equation:

-(24n+16)



We get rid of parentheses

8n-24n-16+4=0

We add all the numbers together, and all the variables

-16n-12=0

We move all terms containing n to the left, all other terms to the right

-16n=12

n=12/-16

n=-3/4

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