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4y=3/2y-1
We move all terms to the left:
4y-(3/2y-1)=0
Domain of the equation: 2y-1)!=0We get rid of parentheses
y∈R
4y-3/2y+1=0
We multiply all the terms by the denominator
4y*2y+1*2y-3=0
Wy multiply elements
8y^2+2y-3=0
a = 8; b = 2; c = -3;
Δ = b2-4ac
Δ = 22-4·8·(-3)
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-10}{2*8}=\frac{-12}{16} =-3/4 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+10}{2*8}=\frac{8}{16} =1/2 $
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