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8(2x+1)+6=5(x-3)+7
We move all terms to the left:
8(2x+1)+6-(5(x-3)+7)=0
We multiply parentheses
16x-(5(x-3)+7)+8+6=0
We calculate terms in parentheses: -(5(x-3)+7), so:We add all the numbers together, and all the variables
5(x-3)+7
We multiply parentheses
5x-15+7
We add all the numbers together, and all the variables
5x-8
Back to the equation:
-(5x-8)
16x-(5x-8)+14=0
We get rid of parentheses
16x-5x+8+14=0
We add all the numbers together, and all the variables
11x+22=0
We move all terms containing x to the left, all other terms to the right
11x=-22
x=-22/11
x=-2
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