4y2=-6y-3y2

Solution for 4y2=-6y-3y2 equation:

4y^2=-6y-3y^2

We move all terms to the left:

4y^2-(-6y-3y^2)=0

We get rid of parentheses

4y^2+3y^2+6y=0

We add all the numbers together, and all the variables

7y^2+6y=0

a = 7; b = 6; c = 0;
Δ = b2-4ac
Δ = 62-4·7·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-6}{2*7}=\frac{-12}{14}
=-6/7
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+6}{2*7}=\frac{0}{14}
=0
$