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x=3x^2+6x+5
We move all terms to the left:
x-(3x^2+6x+5)=0
We get rid of parentheses
-3x^2+x-6x-5=0
We add all the numbers together, and all the variables
-3x^2-5x-5=0
a = -3; b = -5; c = -5;
Δ = b2-4ac
Δ = -52-4·(-3)·(-5)
Δ = -35
Delta is less than zero, so there is no solution for the equation
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