4y-6+2(3y+6)=-6(y+2)

Solution for 4y-6+2(3y+6)=-6(y+2) equation:

4y-6+2(3y+6)=-6(y+2)

We move all terms to the left:

4y-6+2(3y+6)-(-6(y+2))=0

We multiply parentheses

4y+6y-(-6(y+2))+12-6=0


We calculate terms in parentheses: -(-6(y+2)), so:

-6(y+2)

We multiply parentheses

-6y-12

Back to the equation:

-(-6y-12)


We add all the numbers together, and all the variables

10y-(-6y-12)+6=0

We get rid of parentheses

10y+6y+12+6=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8