180=100+(x+12)+x

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Solution for 180=100+(x+12)+x equation: 



180=100+(x+12)+x

We move all terms to the left:

180-(100+(x+12)+x)=0



We calculate terms in parentheses: -(100+(x+12)+x), so:

100+(x+12)+x

determiningTheFunctionDomain
(x+12)+x+100

We add all the numbers together, and all the variables

x+(x+12)+100

We get rid of parentheses

x+x+12+100

We add all the numbers together, and all the variables

2x+112

Back to the equation:

-(2x+112)



We get rid of parentheses

-2x-112+180=0

We add all the numbers together, and all the variables

-2x+68=0

We move all terms containing x to the left, all other terms to the right

-2x=-68

x=-68/-2

x=+34

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