4y-6+2(2y+4)=-2(y+1)

Solution for 4y-6+2(2y+4)=-2(y+1) equation:

4y-6+2(2y+4)=-2(y+1)

We move all terms to the left:

4y-6+2(2y+4)-(-2(y+1))=0

We multiply parentheses

4y+4y-(-2(y+1))+8-6=0


We calculate terms in parentheses: -(-2(y+1)), so:

-2(y+1)

We multiply parentheses

-2y-2

Back to the equation:

-(-2y-2)


We add all the numbers together, and all the variables

8y-(-2y-2)+2=0

We get rid of parentheses

8y+2y+2+2=0

We add all the numbers together, and all the variables

10y+4=0

We move all terms containing y to the left, all other terms to the right

10y=-4

y=-4/10

y=-2/5