-2(6u-4)+4u=8+2(4u-5)

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Solution for -2(6u-4)+4u=8+2(4u-5) equation:



-2(6u-4)+4u=8+2(4u-5)
We move all terms to the left:
-2(6u-4)+4u-(8+2(4u-5))=0
We add all the numbers together, and all the variables
4u-2(6u-4)-(8+2(4u-5))=0
We multiply parentheses
4u-12u-(8+2(4u-5))+8=0
We calculate terms in parentheses: -(8+2(4u-5)), so:
8+2(4u-5)
determiningTheFunctionDomain 2(4u-5)+8
We multiply parentheses
8u-10+8
We add all the numbers together, and all the variables
8u-2
Back to the equation:
-(8u-2)
We add all the numbers together, and all the variables
-8u-(8u-2)+8=0
We get rid of parentheses
-8u-8u+2+8=0
We add all the numbers together, and all the variables
-16u+10=0
We move all terms containing u to the left, all other terms to the right
-16u=-10
u=-10/-16
u=5/8

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