4y-39=-3(y-1)

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Solution for 4y-39=-3(y-1) equation: 



4y-39=-3(y-1)

We move all terms to the left:

4y-39-(-3(y-1))=0



We calculate terms in parentheses: -(-3(y-1)), so:

-3(y-1)

We multiply parentheses

-3y+3

Back to the equation:

-(-3y+3)



We get rid of parentheses

4y+3y-3-39=0

We add all the numbers together, and all the variables

7y-42=0

We move all terms containing y to the left, all other terms to the right

7y=42

y=42/7

y=6

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