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0.25=500x-5400/500x
We move all terms to the left:
0.25-(500x-5400/500x)=0
Domain of the equation: 500x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+500x-5400/500x)+0.25=0
We get rid of parentheses
-500x+5400/500x+0.25=0
We multiply all the terms by the denominator
-500x*500x+(0.25)*500x+5400=0
We multiply parentheses
-500x*500x+125x+5400=0
Wy multiply elements
-250000x^2+125x+5400=0
a = -250000; b = 125; c = +5400;
Δ = b2-4ac
Δ = 1252-4·(-250000)·5400
Δ = 5400015625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5400015625}=\sqrt{15625*345601}=\sqrt{15625}*\sqrt{345601}=125\sqrt{345601}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(125)-125\sqrt{345601}}{2*-250000}=\frac{-125-125\sqrt{345601}}{-500000} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(125)+125\sqrt{345601}}{2*-250000}=\frac{-125+125\sqrt{345601}}{-500000} $
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