4y-3(y-4)+1=6

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Solution for 4y-3(y-4)+1=6 equation:


Simplifying
4y + -3(y + -4) + 1 = 6

Reorder the terms:
4y + -3(-4 + y) + 1 = 6
4y + (-4 * -3 + y * -3) + 1 = 6
4y + (12 + -3y) + 1 = 6

Reorder the terms:
12 + 1 + 4y + -3y = 6

Combine like terms: 12 + 1 = 13
13 + 4y + -3y = 6

Combine like terms: 4y + -3y = 1y
13 + 1y = 6

Solving
13 + 1y = 6

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-13' to each side of the equation.
13 + -13 + 1y = 6 + -13

Combine like terms: 13 + -13 = 0
0 + 1y = 6 + -13
1y = 6 + -13

Combine like terms: 6 + -13 = -7
1y = -7

Divide each side by '1'.
y = -7

Simplifying
y = -7

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