(8y+1)(8y-1)=0

Solution for (8y+1)(8y-1)=0 equation:

Simplifying
(8y + 1)(8y + -1) = 0

Reorder the terms:
(1 + 8y)(8y + -1) = 0

Reorder the terms:
(1 + 8y)(-1 + 8y) = 0

Multiply (1 + 8y) * (-1 + 8y)
(1(-1 + 8y) + 8y * (-1 + 8y)) = 0
((-1 * 1 + 8y * 1) + 8y * (-1 + 8y)) = 0
((-1 + 8y) + 8y * (-1 + 8y)) = 0
(-1 + 8y + (-1 * 8y + 8y * 8y)) = 0
(-1 + 8y + (-8y + 64y2)) = 0

Combine like terms: 8y + -8y = 0
(-1 + 0 + 64y2) = 0
(-1 + 64y2) = 0

Solving
-1 + 64y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 64y2 = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 64y2 = 0 + 1
64y2 = 0 + 1

Combine like terms: 0 + 1 = 1
64y2 = 1

Divide each side by '64'.
y2 = 0.015625

Simplifying
y2 = 0.015625

Take the square root of each side:
y = {-0.125, 0.125}