4y-2(1-y)=-41

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Solution for 4y-2(1-y)=-41 equation: 



4y-2(1-y)=-41

We move all terms to the left:

4y-2(1-y)-(-41)=0

We add all the numbers together, and all the variables

4y-2(-1y+1)-(-41)=0

We add all the numbers together, and all the variables

4y-2(-1y+1)+41=0

We multiply parentheses

4y+2y-2+41=0

We add all the numbers together, and all the variables

6y+39=0

We move all terms containing y to the left, all other terms to the right

6y=-39

y=-39/6

y=-6+1/2

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