4y+1-y=3(y+2)-5

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Solution for 4y+1-y=3(y+2)-5 equation: 



4y+1-y=3(y+2)-5

We move all terms to the left:

4y+1-y-(3(y+2)-5)=0

We add all the numbers together, and all the variables

3y-(3(y+2)-5)+1=0



We calculate terms in parentheses: -(3(y+2)-5), so:

3(y+2)-5

We multiply parentheses

3y+6-5

We add all the numbers together, and all the variables

3y+1

Back to the equation:

-(3y+1)



We get rid of parentheses

3y-3y-1+1=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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