7=(3)(2)+b2)10=(1/2)(8)+b

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Solution for 7=(3)(2)+b2)10=(1/2)(8)+b equation: 



7=(3)(2)+b2)10=(1/2)(8)+b

We move all terms to the left:

7-((3)(2)+b2)10)=0

We add all the numbers together, and all the variables

-(+b^2+32)10)+7=0

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