4y(2y+6)=328

Solution for 4y(2y+6)=328 equation:

4y(2y+6)=328

We move all terms to the left:

4y(2y+6)-(328)=0

We multiply parentheses

8y^2+24y-328=0

a = 8; b = 24; c = -328;
Δ = b2-4ac
Δ = 242-4·8·(-328)
Δ = 11072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{11072}=\sqrt{64*173}=\sqrt{64}*\sqrt{173}=8\sqrt{173}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-8\sqrt{173}}{2*8}=\frac{-24-8\sqrt{173}}{16}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+8\sqrt{173}}{2*8}=\frac{-24+8\sqrt{173}}{16}
$