-3n+10=3(n+4)-2

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Solution for -3n+10=3(n+4)-2 equation: 



-3n+10=3(n+4)-2

We move all terms to the left:

-3n+10-(3(n+4)-2)=0



We calculate terms in parentheses: -(3(n+4)-2), so:

3(n+4)-2

We multiply parentheses

3n+12-2

We add all the numbers together, and all the variables

3n+10

Back to the equation:

-(3n+10)



We get rid of parentheses

-3n-3n-10+10=0

We add all the numbers together, and all the variables

-6n=0

n=0/-6

n=0

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