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4x=1/2x*5
We move all terms to the left:
4x-(1/2x*5)=0
Domain of the equation: 2x*5)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
4x-(+1/2x*5)=0
We get rid of parentheses
4x-1/2x*5=0
We multiply all the terms by the denominator
4x*2x*5-1=0
Wy multiply elements
40x^2*5-1=0
Wy multiply elements
200x^2-1=0
a = 200; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·200·(-1)
Δ = 800
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{800}=\sqrt{400*2}=\sqrt{400}*\sqrt{2}=20\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{2}}{2*200}=\frac{0-20\sqrt{2}}{400} =-\frac{20\sqrt{2}}{400} =-\frac{\sqrt{2}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{2}}{2*200}=\frac{0+20\sqrt{2}}{400} =\frac{20\sqrt{2}}{400} =\frac{\sqrt{2}}{20} $
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