4x2=38x

Solution for 4x2=38x equation:

4x^2=38x

We move all terms to the left:

4x^2-(38x)=0

a = 4; b = -38; c = 0;
Δ = b2-4ac
Δ = -382-4·4·0
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-38)-38}{2*4}=\frac{0}{8}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-38)+38}{2*4}=\frac{76}{8}
=9+1/2
$