4x2-150x+250=0

Solution for 4x2-150x+250=0 equation:

4x^2-150x+250=0

a = 4; b = -150; c = +250;
Δ = b2-4ac
Δ = -1502-4·4·250
Δ = 18500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{18500}=\sqrt{100*185}=\sqrt{100}*\sqrt{185}=10\sqrt{185}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-150)-10\sqrt{185}}{2*4}=\frac{150-10\sqrt{185}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-150)+10\sqrt{185}}{2*4}=\frac{150+10\sqrt{185}}{8}
$