If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2-12x-1=0
a = 4; b = -12; c = -1;
Δ = b2-4ac
Δ = -122-4·4·(-1)
Δ = 160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{160}=\sqrt{16*10}=\sqrt{16}*\sqrt{10}=4\sqrt{10}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{10}}{2*4}=\frac{12-4\sqrt{10}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{10}}{2*4}=\frac{12+4\sqrt{10}}{8} $
| p^2+0*p+5=69 | | p^2+2*p+1=16 | | p^+2*p-15=0 | | p^+0*p+5=69 | | (x+3)^2=99 | | G=12a+37 | | F=7×2b+3×8-4×b+6×7 | | E=17(14n-9) | | 6x+8x=64 | | p^+0*p-64=0 | | 4p^+0*p+3=103 | | 2.5x/x=0 | | 6x-1+6x-1+4x+6+4x+6=180 | | -11x=297 | | (2x-17+9)(9)=(18)(8) | | -18/11=-90/3x | | --8v/3=-64 | | 5u/7=-64 | | 2/3f=124 | | X-(x/10)=45 | | 2(x–6)=2(x–4) | | 4(x–2)=3x–10 | | 3(4x+2)=7-4(1-2x) | | 3(4x+2)=7-4(1-2x) | | 2^x=29 | | 2^x+5^x=29 | | 0.5(2m-18)+3m=43 | | 3^(4x+1)=5 | | 1/5(p+1)(2p-5)=0 | | C*^2-4c-2=0 | | 20*x=10^x | | 7 |