3(4x+2)=7-4(1-2x)

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Solution for 3(4x+2)=7-4(1-2x) equation: 



3(4x+2)=7-4(1-2x)

We move all terms to the left:

3(4x+2)-(7-4(1-2x))=0

We add all the numbers together, and all the variables

3(4x+2)-(7-4(-2x+1))=0

We multiply parentheses

12x-(7-4(-2x+1))+6=0



We calculate terms in parentheses: -(7-4(-2x+1)), so:

7-4(-2x+1)

determiningTheFunctionDomain
-4(-2x+1)+7

We multiply parentheses

8x-4+7

We add all the numbers together, and all the variables

8x+3

Back to the equation:

-(8x+3)



We get rid of parentheses

12x-8x-3+6=0

We add all the numbers together, and all the variables

4x+3=0

We move all terms containing x to the left, all other terms to the right

4x=-3

x=-3/4

x=-3/4

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