4x2+34=(x+1)(4x-3)

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Solution for 4x2+34=(x+1)(4x-3) equation: 



4x^2+34=(x+1)(4x-3)

We move all terms to the left:

4x^2+34-((x+1)(4x-3))=0

We multiply parentheses ..

4x^2-((+4x^2-3x+4x-3))+34=0



We calculate terms in parentheses: -((+4x^2-3x+4x-3)), so:

(+4x^2-3x+4x-3)

We get rid of parentheses

4x^2-3x+4x-3

We add all the numbers together, and all the variables

4x^2+x-3

Back to the equation:

-(4x^2+x-3)



We get rid of parentheses

4x^2-4x^2-x+3+34=0

We add all the numbers together, and all the variables

-1x+37=0

We move all terms containing x to the left, all other terms to the right

-x=-37

x=-37/-1

x=+37

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