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(8/5x)-(2/3x)=(4/15)
We move all terms to the left:
(8/5x)-(2/3x)-((4/15))=0
Domain of the equation: 5x)!=0
x!=0/1
x!=0
x∈R
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+8/5x)-(+2/3x)-((+4/15))=0
We get rid of parentheses
8/5x-2/3x-((+4/15))=0
We calculate fractions
We do not support expression: x^3
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