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4x^2+2x=72
We move all terms to the left:
4x^2+2x-(72)=0
a = 4; b = 2; c = -72;
Δ = b2-4ac
Δ = 22-4·4·(-72)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-34}{2*4}=\frac{-36}{8} =-4+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+34}{2*4}=\frac{32}{8} =4 $
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