X2-3x=3x2-4x

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Solution for X2-3x=3x2-4x equation:



X2-3X=3X^2-4X
We move all terms to the left:
X2-3X-(3X^2-4X)=0
We add all the numbers together, and all the variables
X^2-3X-(3X^2-4X)=0
We get rid of parentheses
X^2-3X^2-3X+4X=0
We add all the numbers together, and all the variables
-2X^2+X=0
a = -2; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-2)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-2}=\frac{-2}{-4} =1/2 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-2}=\frac{0}{-4} =0 $

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