4x2+12x-49=0

Solution for 4x2+12x-49=0 equation:

4x^2+12x-49=0

a = 4; b = 12; c = -49;
Δ = b2-4ac
Δ = 122-4·4·(-49)
Δ = 928
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{928}=\sqrt{16*58}=\sqrt{16}*\sqrt{58}=4\sqrt{58}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4\sqrt{58}}{2*4}=\frac{-12-4\sqrt{58}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4\sqrt{58}}{2*4}=\frac{-12+4\sqrt{58}}{8}
$