4(2x+3)+8x=9(x-1)+18

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Solution for 4(2x+3)+8x=9(x-1)+18 equation: 



4(2x+3)+8x=9(x-1)+18

We move all terms to the left:

4(2x+3)+8x-(9(x-1)+18)=0

We add all the numbers together, and all the variables

8x+4(2x+3)-(9(x-1)+18)=0

We multiply parentheses

8x+8x-(9(x-1)+18)+12=0



We calculate terms in parentheses: -(9(x-1)+18), so:

9(x-1)+18

We multiply parentheses

9x-9+18

We add all the numbers together, and all the variables

9x+9

Back to the equation:

-(9x+9)



We add all the numbers together, and all the variables

16x-(9x+9)+12=0

We get rid of parentheses

16x-9x-9+12=0

We add all the numbers together, and all the variables

7x+3=0

We move all terms containing x to the left, all other terms to the right

7x=-3

x=-3/7

x=-3/7

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