4x-8x+12=3x+40

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Solution for 4x-8x+12=3x+40 equation: 



4x-8x+12=3x+40

We move all terms to the left:

4x-8x+12-(3x+40)=0

We add all the numbers together, and all the variables

-4x-(3x+40)+12=0

We get rid of parentheses

-4x-3x-40+12=0

We add all the numbers together, and all the variables

-7x-28=0

We move all terms containing x to the left, all other terms to the right

-7x=28

x=28/-7

x=-4

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