30t2+80t-80=0

Solution for 30t2+80t-80=0 equation:

30t^2+80t-80=0

a = 30; b = 80; c = -80;
Δ = b2-4ac
Δ = 802-4·30·(-80)
Δ = 16000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16000}=\sqrt{1600*10}=\sqrt{1600}*\sqrt{10}=40\sqrt{10}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-40\sqrt{10}}{2*30}=\frac{-80-40\sqrt{10}}{60}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+40\sqrt{10}}{2*30}=\frac{-80+40\sqrt{10}}{60}
$