2y+8=-2(3y-2)

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Solution for 2y+8=-2(3y-2) equation: 



2y+8=-2(3y-2)

We move all terms to the left:

2y+8-(-2(3y-2))=0



We calculate terms in parentheses: -(-2(3y-2)), so:

-2(3y-2)

We multiply parentheses

-6y+4

Back to the equation:

-(-6y+4)



We get rid of parentheses

2y+6y-4+8=0

We add all the numbers together, and all the variables

8y+4=0

We move all terms containing y to the left, all other terms to the right

8y=-4

y=-4/8

y=-1/2

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