4x-8+2x=4(x+3)-2

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Solution for 4x-8+2x=4(x+3)-2 equation: 



4x-8+2x=4(x+3)-2

We move all terms to the left:

4x-8+2x-(4(x+3)-2)=0

We add all the numbers together, and all the variables

6x-(4(x+3)-2)-8=0



We calculate terms in parentheses: -(4(x+3)-2), so:

4(x+3)-2

We multiply parentheses

4x+12-2

We add all the numbers together, and all the variables

4x+10

Back to the equation:

-(4x+10)



We get rid of parentheses

6x-4x-10-8=0

We add all the numbers together, and all the variables

2x-18=0

We move all terms containing x to the left, all other terms to the right

2x=18

x=18/2

x=9

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