(8/3)x-(2/3)x=x-4

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Solution for (8/3)x-(2/3)x=x-4 equation: 



(8/3)x-(2/3)x=x-4

We move all terms to the left:

(8/3)x-(2/3)x-(x-4)=0



Domain of the equation: 3)x!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(+8/3)x-(+2/3)x-(x-4)=0

We multiply parentheses

8x^2-2x^2-(x-4)=0

We get rid of parentheses

8x^2-2x^2-x+4=0

We add all the numbers together, and all the variables

6x^2-1x+4=0

a = 6; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·6·4
Δ = -95
Delta is less than zero, so there is no solution for the equation

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