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4x-6=-1/2x+3
We move all terms to the left:
4x-6-(-1/2x+3)=0
Domain of the equation: 2x+3)!=0We get rid of parentheses
x∈R
4x+1/2x-3-6=0
We multiply all the terms by the denominator
4x*2x-3*2x-6*2x+1=0
Wy multiply elements
8x^2-6x-12x+1=0
We add all the numbers together, and all the variables
8x^2-18x+1=0
a = 8; b = -18; c = +1;
Δ = b2-4ac
Δ = -182-4·8·1
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-2\sqrt{73}}{2*8}=\frac{18-2\sqrt{73}}{16} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+2\sqrt{73}}{2*8}=\frac{18+2\sqrt{73}}{16} $
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