1000=0.35(x+x/0.08)+0.65(1000+2x)

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Solution for 1000=0.35(x+x/0.08)+0.65(1000+2x) equation: 



1000=0.35(x+x/0.08)+0.65(1000+2x)

We move all terms to the left:

1000-(0.35(x+x/0.08)+0.65(1000+2x))=0



Domain of the equation: 0.08)+0.65(1000+2x))!=0

x∈R



We add all the numbers together, and all the variables

-(0.35(+x+x/0.08)+0.65(2x+1000))+1000=0

We multiply all the terms by the denominator


-(0.35(+x+x+1000*0.08)+0.65(2x+1000))=0



We calculate terms in parentheses: -(0.35(+x+x+1000*0.08)+0.65(2x+1000)), so:

0.35(+x+x+1000*0.08)+0.65(2x+1000)

We add all the numbers together, and all the variables

0.35(2x+80)+0.65(2x+1000)

We multiply parentheses

0.7x+1.3x+28+650

We add all the numbers together, and all the variables

2x+678

Back to the equation:

-(2x+678)



We get rid of parentheses

-2x-678=0

We move all terms containing x to the left, all other terms to the right

-2x=678

x=678/-2

x=-339

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