4x-5(x+3)=3(x+1)-2

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Solution for 4x-5(x+3)=3(x+1)-2 equation: 



4x-5(x+3)=3(x+1)-2

We move all terms to the left:

4x-5(x+3)-(3(x+1)-2)=0

We multiply parentheses

4x-5x-(3(x+1)-2)-15=0



We calculate terms in parentheses: -(3(x+1)-2), so:

3(x+1)-2

We multiply parentheses

3x+3-2

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

-1x-(3x+1)-15=0

We get rid of parentheses

-1x-3x-1-15=0

We add all the numbers together, and all the variables

-4x-16=0

We move all terms containing x to the left, all other terms to the right

-4x=16

x=16/-4

x=-4

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