3(n-2)=5(n-4)+2

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Solution for 3(n-2)=5(n-4)+2 equation: 



3(n-2)=5(n-4)+2

We move all terms to the left:

3(n-2)-(5(n-4)+2)=0

We multiply parentheses

3n-(5(n-4)+2)-6=0



We calculate terms in parentheses: -(5(n-4)+2), so:

5(n-4)+2

We multiply parentheses

5n-20+2

We add all the numbers together, and all the variables

5n-18

Back to the equation:

-(5n-18)



We get rid of parentheses

3n-5n+18-6=0

We add all the numbers together, and all the variables

-2n+12=0

We move all terms containing n to the left, all other terms to the right

-2n=-12

n=-12/-2

n=+6

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