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4x-2(x-6)=2(x+1)+6
We move all terms to the left:
4x-2(x-6)-(2(x+1)+6)=0
We multiply parentheses
4x-2x-(2(x+1)+6)+12=0
We calculate terms in parentheses: -(2(x+1)+6), so:We add all the numbers together, and all the variables
2(x+1)+6
We multiply parentheses
2x+2+6
We add all the numbers together, and all the variables
2x+8
Back to the equation:
-(2x+8)
2x-(2x+8)+12=0
We get rid of parentheses
2x-2x-8+12=0
We add all the numbers together, and all the variables
4!=0
There is no solution for this equation
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