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(X+4)(X+5)=70
We move all terms to the left:
(X+4)(X+5)-(70)=0
We multiply parentheses ..
(+X^2+5X+4X+20)-70=0
We get rid of parentheses
X^2+5X+4X+20-70=0
We add all the numbers together, and all the variables
X^2+9X-50=0
a = 1; b = 9; c = -50;
Δ = b2-4ac
Δ = 92-4·1·(-50)
Δ = 281
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{281}}{2*1}=\frac{-9-\sqrt{281}}{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{281}}{2*1}=\frac{-9+\sqrt{281}}{2} $
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