4x-2(x-4)=-8+5x-5

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Solution for 4x-2(x-4)=-8+5x-5 equation: 



4x-2(x-4)=-8+5x-5

We move all terms to the left:

4x-2(x-4)-(-8+5x-5)=0

We add all the numbers together, and all the variables

4x-2(x-4)-(5x-13)=0

We multiply parentheses

4x-2x-(5x-13)+8=0

We get rid of parentheses

4x-2x-5x+13+8=0

We add all the numbers together, and all the variables

-3x+21=0

We move all terms containing x to the left, all other terms to the right

-3x=-21

x=-21/-3

x=+7

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