4x-2(x-3)=3(x-4)

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Solution for 4x-2(x-3)=3(x-4) equation: 



4x-2(x-3)=3(x-4)

We move all terms to the left:

4x-2(x-3)-(3(x-4))=0

We multiply parentheses

4x-2x-(3(x-4))+6=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

2x-(3x-12)+6=0

We get rid of parentheses

2x-3x+12+6=0

We add all the numbers together, and all the variables

-1x+18=0

We move all terms containing x to the left, all other terms to the right

-x=-18

x=-18/-1

x=+18

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