5/(2x)+4/(3x)=7

Solution for 5/(2x)+4/(3x)=7 equation:

5/(2x)+4/(3x)=7

We move all terms to the left:

5/(2x)+4/(3x)-(7)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R


We calculate fractions


15x/6x^2+8x/6x^2-7=0

We multiply all the terms by the denominator


15x+8x-7*6x^2=0

We add all the numbers together, and all the variables

23x-7*6x^2=0

Wy multiply elements

-42x^2+23x=0

a = -42; b = 23; c = 0;
Δ = b2-4ac
Δ = 232-4·(-42)·0
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{529}=23$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-23}{2*-42}=\frac{-46}{-84}
=23/42
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+23}{2*-42}=\frac{0}{-84}
=0
$