4x-2(x-3)+1=9-7(x-1)

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Solution for 4x-2(x-3)+1=9-7(x-1) equation: 



4x-2(x-3)+1=9-7(x-1)

We move all terms to the left:

4x-2(x-3)+1-(9-7(x-1))=0

We multiply parentheses

4x-2x-(9-7(x-1))+6+1=0



We calculate terms in parentheses: -(9-7(x-1)), so:

9-7(x-1)

determiningTheFunctionDomain
-7(x-1)+9

We multiply parentheses

-7x+7+9

We add all the numbers together, and all the variables

-7x+16

Back to the equation:

-(-7x+16)



We add all the numbers together, and all the variables

2x-(-7x+16)+7=0

We get rid of parentheses

2x+7x-16+7=0

We add all the numbers together, and all the variables

9x-9=0

We move all terms containing x to the left, all other terms to the right

9x=9

x=9/9

x=1

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