8(v+3)-5(v-2)=1=6v+2v+3

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Solution for 8(v+3)-5(v-2)=1=6v+2v+3 equation: 



8(v+3)-5(v-2)=1=6v+2v+3

We move all terms to the left:

8(v+3)-5(v-2)-(1)=0

We multiply parentheses

8v-5v+24+10-1=0

We add all the numbers together, and all the variables

3v+33=0

We move all terms containing v to the left, all other terms to the right

3v=-33

v=-33/3

v=-11

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