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4x-2(x+4)=2(x+1)-6
We move all terms to the left:
4x-2(x+4)-(2(x+1)-6)=0
We multiply parentheses
4x-2x-(2(x+1)-6)-8=0
We calculate terms in parentheses: -(2(x+1)-6), so:We add all the numbers together, and all the variables
2(x+1)-6
We multiply parentheses
2x+2-6
We add all the numbers together, and all the variables
2x-4
Back to the equation:
-(2x-4)
2x-(2x-4)-8=0
We get rid of parentheses
2x-2x+4-8=0
We add all the numbers together, and all the variables
-4!=0
There is no solution for this equation
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