4x-2(4-3x)=3(x-4)-31

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Solution for 4x-2(4-3x)=3(x-4)-31 equation: 



4x-2(4-3x)=3(x-4)-31

We move all terms to the left:

4x-2(4-3x)-(3(x-4)-31)=0

We add all the numbers together, and all the variables

4x-2(-3x+4)-(3(x-4)-31)=0

We multiply parentheses

4x+6x-(3(x-4)-31)-8=0



We calculate terms in parentheses: -(3(x-4)-31), so:

3(x-4)-31

We multiply parentheses

3x-12-31

We add all the numbers together, and all the variables

3x-43

Back to the equation:

-(3x-43)



We add all the numbers together, and all the variables

10x-(3x-43)-8=0

We get rid of parentheses

10x-3x+43-8=0

We add all the numbers together, and all the variables

7x+35=0

We move all terms containing x to the left, all other terms to the right

7x=-35

x=-35/7

x=-5

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